Study For Your Career

  
As you know, pointers are the variable which stores the address of another variable or pointer.
Consider this basic one dimension array ' arr[ ] '

int arr[ ] = { 10 , 20 , 30 , 40 , 50 } ;
printf ( " %d %d ", *arr , arr[0] ); 

The output to this program is 10 10.

When mentioning the name of the array 'arr' we get its base address. Thus *arr refers to the zeroth element of the array, i.e , 10.

similarly

int arr[ ] = { 10 , 20 , 30 , 40 , 50 };
for(int i=0 ; i<5 ; i++ )
   printf ( " %d %d \n"  , *( arr + i )  , arr[i] );

We get the output as
10 10
20 20
30 30
40 40
50 50

When we say, arr[i] , the C compiler internally converts it to *( arr + i ) . Hence this means that the following notations are same:

arr [ i ] = *( arr + i ) = *( i + arr ) = i [ arr ] 

To prove this compile the below program:

int main( ) {
   int arr[ ] = { 10 , 20 , 30 , 40 , 50 };
   int i;
   for( i=0 ; i < 5 ; i++ ){
      if ( arr[i] = = i[arr] )
         printf(" True ");
      else
         printf(" False ");
   }
   return 0;
}

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