Ans. The greatest common divisor of two positive integers is the largest integer that is a divisor of both of them. For, example, 3 is the greatest common divisor of 6 and 15, and 1 is the greatest common divisor of 7 and 11.
Hence , here is a recursive function that computest the greatest common divisor of two positive integers:
// in file gcd.c
#include<stdio.h>
#include <conio.h>
int gcd ( int a, int b ) {
int r;
if ( ( r = a%b ) == 0 )
return b;
else
return gcd ( b , r );
}
void main(void){
int p,q;
printf("\n Enter two numbers: ");
scanf("%d %d",&p,&q);
printf("\n The gcd is %d ",gcd(p,q));
getch( );
}
________
For ex: if a=15 and b=6 , then
(r = 3) !=0 hence again the func executes with value a=6 , b=3
Now , the value of r become 0 .
Hence the value of b ,(i.e) 3 , is returned .
Please post if you have a better solution.
Hence , here is a recursive function that computest the greatest common divisor of two positive integers:
// in file gcd.c
#include<stdio.h>
#include <conio.h>
int gcd ( int a, int b ) {
int r;
if ( ( r = a%b ) == 0 )
return b;
else
return gcd ( b , r );
}
void main(void){
int p,q;
printf("\n Enter two numbers: ");
scanf("%d %d",&p,&q);
printf("\n The gcd is %d ",gcd(p,q));
getch( );
}
________
For ex: if a=15 and b=6 , then
(r = 3) !=0 hence again the func executes with value a=6 , b=3
Now , the value of r become 0 .
Hence the value of b ,(i.e) 3 , is returned .
Please post if you have a better solution.
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program questions
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